Optimal. Leaf size=131 \[ \frac{a}{4 d \sqrt{a \sec (c+d x)+a}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a \sec (c+d x)+a}}-\frac{2 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{a}}\right )}{d}+\frac{7 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} d} \]
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Rubi [A] time = 0.118459, antiderivative size = 131, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {3880, 103, 152, 156, 63, 207} \[ \frac{a}{4 d \sqrt{a \sec (c+d x)+a}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a \sec (c+d x)+a}}-\frac{2 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{a}}\right )}{d}+\frac{7 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} d} \]
Antiderivative was successfully verified.
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Rule 3880
Rule 103
Rule 152
Rule 156
Rule 63
Rule 207
Rubi steps
\begin{align*} \int \cot ^3(c+d x) \sqrt{a+a \sec (c+d x)} \, dx &=\frac{a^4 \operatorname{Subst}\left (\int \frac{1}{x (-a+a x)^2 (a+a x)^{3/2}} \, dx,x,\sec (c+d x)\right )}{d}\\ &=\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a+a \sec (c+d x)}}-\frac{a \operatorname{Subst}\left (\int \frac{2 a^2+\frac{3 a^2 x}{2}}{x (-a+a x) (a+a x)^{3/2}} \, dx,x,\sec (c+d x)\right )}{2 d}\\ &=\frac{a}{4 d \sqrt{a+a \sec (c+d x)}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a+a \sec (c+d x)}}+\frac{\operatorname{Subst}\left (\int \frac{-2 a^4+\frac{a^4 x}{4}}{x (-a+a x) \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{2 a^2 d}\\ &=\frac{a}{4 d \sqrt{a+a \sec (c+d x)}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a+a \sec (c+d x)}}+\frac{a \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{d}-\frac{\left (7 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{(-a+a x) \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{8 d}\\ &=\frac{a}{4 d \sqrt{a+a \sec (c+d x)}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a+a \sec (c+d x)}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{-1+\frac{x^2}{a}} \, dx,x,\sqrt{a+a \sec (c+d x)}\right )}{d}-\frac{(7 a) \operatorname{Subst}\left (\int \frac{1}{-2 a+x^2} \, dx,x,\sqrt{a+a \sec (c+d x)}\right )}{4 d}\\ &=-\frac{2 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a+a \sec (c+d x)}}{\sqrt{a}}\right )}{d}+\frac{7 \sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a+a \sec (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{4 \sqrt{2} d}+\frac{a}{4 d \sqrt{a+a \sec (c+d x)}}+\frac{a}{2 d (1-\sec (c+d x)) \sqrt{a+a \sec (c+d x)}}\\ \end{align*}
Mathematica [C] time = 0.274112, size = 87, normalized size = 0.66 \[ \frac{\cot ^2(c+d x) \sqrt{a (\sec (c+d x)+1)} \left (-7 (\sec (c+d x)-1) \text{Hypergeometric2F1}\left (-\frac{1}{2},1,\frac{1}{2},\frac{1}{2} (\sec (c+d x)+1)\right )+8 (\sec (c+d x)-1) \text{Hypergeometric2F1}\left (-\frac{1}{2},1,\frac{1}{2},\sec (c+d x)+1\right )-2\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.26, size = 267, normalized size = 2. \begin{align*}{\frac{ \left ( \cos \left ( dx+c \right ) \right ) ^{2}-1}{8\,d \left ( \sin \left ( dx+c \right ) \right ) ^{4}}\sqrt{{\frac{a \left ( \cos \left ( dx+c \right ) +1 \right ) }{\cos \left ( dx+c \right ) }}} \left ( 8\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}\arctan \left ( 1/2\,\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}} \right ) +7\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}\arctan \left ({\frac{1}{\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}}} \right ) -8\,\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}\arctan \left ( 1/2\,\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}} \right ) +6\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}-7\,\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}\arctan \left ({\frac{1}{\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}}} \right ) -2\,\cos \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \sec \left (d x + c\right ) + a} \cot \left (d x + c\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.54273, size = 1118, normalized size = 8.53 \begin{align*} \left [\frac{8 \,{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sqrt{a} \log \left (-8 \, a \cos \left (d x + c\right )^{2} + 4 \,{\left (2 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right )\right )} \sqrt{a} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} - 8 \, a \cos \left (d x + c\right ) - a\right ) + 7 \,{\left (\sqrt{2} \cos \left (d x + c\right )^{2} - \sqrt{2}\right )} \sqrt{a} \log \left (\frac{2 \, \sqrt{2} \sqrt{a} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right ) + 3 \, a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right ) - 1}\right ) + 4 \,{\left (3 \, \cos \left (d x + c\right )^{2} - \cos \left (d x + c\right )\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}}}{16 \,{\left (d \cos \left (d x + c\right )^{2} - d\right )}}, -\frac{7 \,{\left (\sqrt{2} \cos \left (d x + c\right )^{2} - \sqrt{2}\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{2} \sqrt{-a} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{a \cos \left (d x + c\right ) + a}\right ) - 8 \,{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sqrt{-a} \arctan \left (\frac{2 \, \sqrt{-a} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{2 \, a \cos \left (d x + c\right ) + a}\right ) - 2 \,{\left (3 \, \cos \left (d x + c\right )^{2} - \cos \left (d x + c\right )\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}}}{8 \,{\left (d \cos \left (d x + c\right )^{2} - d\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \left (\sec{\left (c + d x \right )} + 1\right )} \cot ^{3}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 5.07272, size = 189, normalized size = 1.44 \begin{align*} \frac{\sqrt{2}{\left (\frac{8 \, \sqrt{2} a \arctan \left (\frac{\sqrt{2} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{2 \, \sqrt{-a}}\right )}{\sqrt{-a}} - \frac{7 \, a \arctan \left (\frac{\sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a}} + 2 \, \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} - \frac{\sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}}\right )} \mathrm{sgn}\left (\cos \left (d x + c\right )\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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